Thursday, October 08, 2015

Cartesian product in Scala

val s  = Seq("1","2","3","4")
val t  = Seq("a","b","c","d","e","f")
val u  = Seq("x","y")
val v  = Seq("m","l","n","o","p")

val sq = Seq(s,t,u,v)

sq.foldLeft(Seq(""))((b,a) => b.flatMap{i=>a.map{j=>i+j}})


res9: Seq[String] = List(1axm, 1axl, 1axn, 1axo, 1axp, 1aym, 1ayl, 1ayn, 1ayo, 1ayp, 1bxm, 1bxl, 1bxn, 1bxo, 1bxp, 1bym, 1byl, 1byn, 1byo, 1byp, 1cxm, 1cxl, 1cxn, 1cxo, 1cxp, 1cym, 1cyl, 1cyn, 1cyo, 1cyp, 1dxm, 1dxl, 1dxn, 1dxo, 1dxp, 1dym, 1dyl, 1dyn, 1dyo, 1dyp, 1exm, 1exl, 1exn, 1exo, 1exp, 1eym, 1eyl, 1eyn, 1eyo, 1eyp, 1fxm, 1fxl, 1fxn, 1fxo, 1fxp, 1fym, 1fyl, 1fyn, 1fyo, 1fyp, 2axm, 2axl, 2axn, 2axo, 2axp, 2aym, 2ayl, 2ayn, 2ayo, 2ayp, 2bxm, 2bxl, 2bxn, 2bxo, 2bxp, 2bym, 2byl, 2byn, 2byo, 2byp, 2cxm, 2cxl, 2cxn, 2cxo, 2cxp, 2cym, 2cyl, 2cyn, 2cyo, 2cyp, 2dxm, 2dxl, 2dxn, 2dxo, 2dxp, 2dym, 2dyl, 2dyn, 2dyo, 2dyp, 2exm, 2exl, 2exn, 2exo, 2exp, 2eym, 2eyl, 2eyn, 2eyo, 2eyp, 2fxm, 2fxl, 2fxn, 2fxo, 2fxp, 2fym, 2fyl, 2fyn, 2fyo, 2fyp, 3axm, 3axl, 3axn, 3axo, 3axp, 3aym, 3ayl, 3ayn, 3ayo...

2 comments:

Anonymous said...

Wow, that's wonderful implementation. I was googling for this and made several trials and none of them works as I expect. This solution produces exactly what I want. BTW one can use List instead of Seq. Thanks. Quoc_Anh

thushara said...

Hi Quoc_Anh,
Thanks for the comment. I used a Seq as it is a trait and thus the code is more generalized.